DDW-2025-002546

1
Basic Math
Pre-certification Training
Water Facts
WATER
One Cubic Foot
=7.48 gallons
One ft.
One ft.
One ft.
One Gallon
Weighs
8.34 lbs.
Scale
8.34
How many feet of head would
create a pressure of 130 psi?
•Formula: psi x 2.31 = feet of
head
•130 psi x 2.31 ft/psi =
•300.3 ft
130 psi ? ft.
Pump runs 18 hours and pumps
120,000 gallons what is gpm
pumping rate?
•18 hours x 60 min = 1080 minutes
•120,000 gallons =
1080 min
•111 gpm
? gpmmeter
After 18 hrs. registers
120,000 gallons
How much would 150 gallons of
water weigh?
•Formula: gal. X 8.34 = lbs. of water
•150 gal x 8.34 lbs./gal =
•1,251 lbs.
scales
? lbs.
150 gallons
What is detention time in minutes of 20 ft
diameter tank 16 ft deep with flow of 1.5
MGD?
•20 ft x 20 ft x 0.785 = 314 ft2
•314 ft2 x 16 ft = 5,024 ft3
•5,024 ft3 x 7.48 gal/ft3 = 37,579.5 gal
•37,580 gal = .025 days x 1440 min=
1,500,000gal/day
•36.1 min
? gallons
20 ft 16 ft
1.5 MGD
? minutes detention time
2
How much force on 6" blind
flange with 65 psi?
•6" x 6" x 0.785 = 28.26 in2
•28.26 in2 x 65 psi =
•1,836.9 pounds
? lbs. of force6 inch
65 psi
What would be the maximum pumping
rate of a 30 hp pump with 100 ft of head?
•100 ft of head x ? gpm = 30 hp
3960
•gpm = 3960 x hp
feet of head
•3960 x 30 hp = 118,800 =
100 feet of head 100 feet of head
•1188 gpm 100 ft.
? gpm30 hp
City spends $166,000. per year and sells
750 MG, what is cost per 1,000 gallons?
•750 MG x 1,000,000 = 750,000,000 gallons
•750,000,000 = 750,000 gallons
1,000
•$166,000 =
750,000
•0.22 cents per 1,000 gallons Spends
$166,000
$ per 1,000 gallons ?
750 MG
How many gallons in an 80 ft diameter
tank filled 20 ft?
•80 ft x 80 ft x 0.785 = 5,024 ft2
•5,024 ft2 x 20 ft = 100,480 ft3
•100,480 ft3 x 7.48 gal/ft3 =
•751,590 gallons
80 ft
20 ft? Gallons
How many gallons of water in an 18 inch
pipe that is 5,500 ft long?
•18 in = 1.5 ft x 1.5 ft x 0.785 = 1.766 ft
2
12 in
•1.766 ft2 x 5,500 ft = 9,714 ft3
•9,714 ft3 x 7.48 gal/ft3 =
•72,663 gallons
5,500 ft.
? gallons
18 inch pipe
How long will a 10,000 gallon tank flow
at 250 gpm?
•10,000 gal =
250 gal/min
•40 min
250 gpm
10,000
gallons
? of minutes to drain
3
How many gallons in a rectangular tank
5 ft x 8 ft x 5 ft?
•5 ft x 8 ft x 5 ft = 200 ft3
•200 ft3 x 7.48 gal/ft3 =
•1,496 gallons
5 ft
8 ft
5 ft
? gallons
How many 18 ft long sections of ductile iron
pipe will be needed for 150 ft of line?
•150 ft = 8.33 pieces
18 ft/piece
•9 pieces
? Of 18 ft Pieces in 150 ft
18 ft
How many hours would it take to fill a 90 ft
dia. tank 40 feet high pumping 2,400 gpm?
•90 ft x 90 ft x 0.785 = 6,358.5 ft2
•6,358.5 ft2 x 40 ft = 254,340 ft3
•254,340 ft3 x 7.48 gal/ft3 = 1,902,460 gal.
•1,902,460 gal. = 792.7 min. 792.7 min. =
2,400 gal/min 60 min./hr.
•13.21 hrs. 0.21min x 60 min = 12.6 min.
•13 hrs. and 13 min.
40 ft
90 ft
Hours to fill ?
2,400 gpm
How many pounds of 65% HTH would be
needed to dose 300,000 gal. at 250 mg/L?
•300,000 gal. = 0.3 MG
1,000,000
•0.3 x 250 mg/L x 8.34 =625.5 lbs.
•625.5 lbs. =
65%
•962 lbs.
300,000 gallons
65%
HTH
? lbs. of to chlorinate at 250 mg/L
How many pounds of 65% HTH would be needed
to dose 3,500 ft of 12 inch pipe to
50 mg/L?
•12" = One Foot
12"
•1 ft x 1 ft x 0.785 = 0.785 ft2
•0.785 ft2 x 3,500 ft = 2,747.5 ft3
•2,747.5 ft3 x 7.48 gal/ft3 = 20,550 gal
•20,550 gal. = 0.021 MG x 50 mg/L x 8.34=
1,000,000
•8.757 lbs. = 13.5 lbs.
.65
12”
3,500 ft.
How much 65% HTH to chlorinate this pipe at 50 mg/L?
What would be the cost per day to chlorinate 4
MG at 1.5 mg/L if chlorine cost 20 cents per
pound?
•4 MGD x 1.5 mg/L x 8.34 = 50.04 lbs
•50.04 lbs. x $0.20 per lbs. =
•$10.00
4 MG
1.5 mg/L
Cl2
$0.20 per lb.
4
What would the psi at an outlet at elevation of
4,195 ft if the water level in the tank above is
4,332 ft?
•4,332 ft - 4,195 ft = 137 ft
•137 ft =
2.31 ft/psi.
•59 psi.
4,332 ft
elevation
4,195 ft
elevation
? psi
A leak of 1 pint every 1.5 min. would
leak how many gallons in 30 days?
•1 pint = .667 pints/minute
1.5 minutes
•.667 pints/min x 1440 min/day = 960.48
pints/day
•30 days x 960.48 pints/day = 28814.4 pints
•28814.4 pints =
8 pints/gallon
•3,602 gallons
1 pint every 1.5 min.
How many gallons in one month?
What would be the gpm average of the
following 4 wells that flow at a rate of 250
gpm, 130 gpm, 320 gpm and 165 gpm?
•250 gpm + 130 gpm + 320 gpm + 165
gpm =
•865 gpm
•865 gpm =
4 wells
•216.25 gpm
250 gpm 130 gpm 320 gpm 165 gpm
Average gpm ?
How many lbs. of 65% HTH would be
needed to disinfect 50,000 gal. at 10
mg/L?
•50,000 gal. = 0.05 MG x 10 mg/L x 8.34= 4.17 lbs.
1,000,000
•4.17 lbs. =
0.65
•6.4 lbs.
65%
HTH 50,000 gallons
10 mg/L
? lbs. needed
What is the pumping rate in gpm if
the pump drains 2 ft out of a 25 ft x
35 ft basin in 1 hr.?
•2 ft x 25 ft x 35 ft = 1,750 ft3
•1,750 ft3 x 7.48 gal/ft3 = 13,090 gal.
•13,090 gal.=
60 min.
•218 gpm
35 ft
25 ft
? gpm
2 ft
What is the gpm flow of the following meter
readings taken three days apart?
First reading 59,364,810 gal. Three days
later 59,598,590 gal.
•59,598,590 gal. - 59,364,810 gal = 233,780 gal
•233,780 gal = 233,780 gal.=
1,440 min/day x 3 days 4,320 min.
•54.1 gpm
59,364,810
meter
59,598,590
meter
Thursday 7am
? gpm
Monday 7am 3 days later
5
How long of a 2' wide by 2' deep trench will be
needed to drain water from 1,500' of 8" water
line?•8" = 0.67'
12"
•0.67 x 0.67' x 0.785 = 0.352 ft2 x 1,500’ =528 ft3
•528 ft3 = 528 ft3 =
2' x 2' 4 ft
2
•132 ft
8“ pipe
? ft of trench
2 ft
2 ft
1,500 ft
If a pump runs for 24 hours and
delivers 180,000 gallons, what is the
gpm flow rate?
•24 hours = 1,440 minutes
•180,000 gallons =
1,440 minutes
•125 gpm
180,000 gallons
? gpm
Pump runs 24 hrs.
Pump produces
How many gallons will a 40' high
tank with a circumference of 283'
hold when it is full?
•283 ft = 90 ft dia.
3.14
•90ft x 90 ft x 0.785 = 6,358.5 ft2
•6,358.5 ft2 x 40 ft = 254,340 ft3
•254,340 ft3 x 7.48 gal/ft3 =
•1,902,463 gallons
? dia.
? gallons
Circumference 283 ft.
40 ft
pi = 3.14
What is the per capita production in
gallons per day for a system that
produces 3,000 gpm for a population of
22,000?
•3,000 gpm x 1,440 min/day =
4,320,000 gpd
•4,320,000 gpd =
22,000 people
•196 gpd per capita
22,000 people
? gallons per day
per person
3,000 gpm
What is the maximum gpm pumping rate of a
400 HP pump with 450 ft of head?
•HP = ft of head x gpm
3,960
•400 HP = 450 ft x ? gpm
3,960
•400 HP x 3,960 =
450 ft of head
•3,520 gpm 450 ft. of
head
400 hp ? gpm
What would be the chlorine dosage if 100 lbs. of 65%
HTH was put in a 283 ft circumference tank that had
32 ft of water?
•283 ft = 90 ft x 90 ft x 0.785 = 6,358.5 ft2
3.14
•6,358.5 ft2 x 32 ft = 203,472 ft3
•203,472 ft3x 7.48 gal/ft3 = 1,522,000 gal.
•1,522,000 gallons = 1.52 MG
1,000,000
•1.52 MG x ? mg/l x 8.34 = 100 lbs.
•? mg/l = 100 lbs. = 100 lbs. =
1.52 MG x 8.34 12.68
•7.89 mg/l x 0.65 =
•5.13 mg/l
? dia.
Circumference = 283
ft
32 ft.
100 lbs.
65% HTH feeder
? mg/L
6
What is the total head loss in feet of 5,700 ft.
of 16 in. pipe with a flow of 2,400 gpm if the
head loss is calculated at 0.31 psi per 100 ft.?
•5,700 ft. = 57 x 0.31 psi=
100 ft.
•17.67 ft x .433 =
•7.6 psi
2,400 gpm 16” pipe
5,700 ft.
0.31 ft. of head loss per 100 ft.100 ft.
? total head loss in feet
If a chlorine residual is 1.2 at the chlorinator
and 0.5 in the distribution system, what is the
chlorine demand?
•1.2 mg/l - 0.5 mg/l =
•0.7 mg/l chlorine demand
1.2 mg/L .5 mg/L
Chlorine demand = ? mg/L
Chlorinator
What is the drawdown in a well with
a static water level of 172 ft. and a
pumping water level of 201 ft.?
•201 ft. - 172 ft. =
•29 feet of drawdown
201 ft.
pumping level
172 ft.
static level Drawdown ?
What is the velocity of the water in fps of an 8
inch pipeline with a flow of 520 gpm?
•Q = A x V Q = 520 gpm A = 8 inch
pipe
•520 gpm = 1.16 cfs
448.8 gpm/cfs
•8 in = 0.67 x 0.67 x 0.785 = 0.352 ft2
12 in
•1.16 ft3/sec =
0.352 ft2
•3.3 fps velocity
520 gpm
8” pipe
Velocity = ? feet per second
If the cut stake for a fire hydrant is
marked AC-4.25@ and the hydrant is 7 ft.
6 in. tall, how high will the top be above
the finished grade?
•6" = 0.5 ft
12 in/ft
•7.5 ft. - 4.25 ft. =
•3.25 ft.
7.5’ 4.25’
? ft.
C - 4.25
How many gal. of 5% sodium hypochlorite will
be needed to disinfect a 12 in. diameter well that
is 280 ft. deep with a static water level of 130 ft.
to a dosage of 50 mg/l?
12” diameter
130 ft
? ft
280 ft
5 %
Cl2
? Gallons
NEXT SLIDE
7
CONTINUED
How many gal. of 5% sodium hypochlorite will be
needed to disinfect a 12 in. well that is 280 ft.
deep with a static water level of 130 ft. to a
dosage of 50 mg/l?
•280 ft. - 130 ft. = 150 ft.
•12" = 1 ft. x 1 ft. x 0.785 = 0.785 ft
2
12”
•0.785 ft2 x 150 ft. = 117.75 ft3
•117.75 ft3 x 7.48 gal/ft3= 881 gal.
•881 gal. = 0.001 x 50 mg/l x 8.34= 0.417 lbs.
1,000,000 gal/MGD
•0.417 lbs. =
0.05
•8.34 lbs. or 1 gallon
What depth of water would create a
force of 105 psi.?
•105 psi. x 2.31 ft/psi =
•242.5 feet
105 psi
? feet
How many cfs of water would 2.5
MGD be?
•2.5 MGD x 1.55 cfs/MGD =
•3.875 cfs
2.5 MGD
? CFS
What is the pumping rate of a 400 HP
pump with 600 feet of head?
•HP = ft of head x gpm
3,960
•400 HP = 600 ft x ? gpm
3,960
•400 HP x 3,960 =
600 ft of head
•2,640 gpm
600 ft
400 hp
? gpm
If a 10 ml portion of water developed 3
coliform bacteria colonies what would be
the number of colonies per 100 ml?
•3 colonies = 0.3 colonies/ml
10 ml
•0.3 colonies/ml x 100 ml =
•30 colonies 10
ml
100 ml
? Colonies per
3 colonies per
How many pounds of gas chlorine would be
needed to dose 1.5 mg/l to a 4.25 mile
section of 24 in. pipeline flowing at 2.1 cfs?
•2.1 cfs = 1.35 MGD
1.55 cfs/MGD
•1.35 MGD x 1.5 mg/l x 8.34 =
•16.9 lbs.
24 inch pipe 2.1 cfs
4.25 miles
? lbs. of chlorine
8
What is the contact time for a 10
hour period of a basin being dosed at
0.2 mg/L?
•CT = Chlorine concentration x Time
in min.
•10 hr. x 60 min. = 600 min.
•0.2 mg/L x 600 min. =
•120 CT units
10 hours
? CT units.2 mg/L
Two pumps are running with an output of 2500 gpm. The
pressure gauges read 89 psi on the discharge pipe and the
distance between the gauges and the water level in the
tank is 144 ft. What is the head loss due to friction?
•GPM has nothing to do with figuring the
answer.
•Convert 144 ft to psi 144 x .433 = 62.35 psi
•89 psi - 62.35 psi =
•26.65 psi of head loss
89 psi
144 ft
Head loss due to friction ?
This year your maintenance crew has been given
a work order to paint the 2.5 million gallon
reservoir. You need to figure how much paint it
will require to paint the reservoir inside and out.
The reservoir is 146’ in diameter and 20’ high. A
gallon of paint will cover 150 square feet.
2.5 million gallons 20 ft.
146 ft.
0negallon
Covers
150 sq.ft.
•Formula: Paint required= total area in square
feet divided by coverage, sq. ft. per gallon.
•Top & bottom: 146’ x 146’ x .785 x 3 sides =
•Top & bottom: 50,199 ft2
•Sides= pi () or 3.14 x 146 dia. x 20’ x 2 sides
•Sides = 18,338 ft2
•50,199 ft2 + 18,338 ft2 = 68,537 ft2
•68,537 ft2 =
150 gal./ ft2
•457 gallons of paint
Disinfecting the Reservoir
• After painting the reservoir you need to
disinfect it per AWWA standards.
• Rules say to use AWWA standard C652-92
• One method states you must maintain 50
mg/L residual for 6 hours
• You are using HTH calcium hypochlorite at
65% strength
2.5 million gallons65%
HTH feeder
50 mg/L
• Formula: lbs. per day= MGD x 8.34 x ppm
• Known 50 mg/L and 2.5 MGD
• 2.5 MGD x 8.34 lbs./gal x 50 mg/L =
• 1043 lbs.
• 1043 lbs./.65% =
• 1605 lbs. of HTH
9
A chlorinator is set to feed 12 lbs. per day to a
flow of 300 GPM. What is the dose in mg/L?
•Dose mg/L = lbs. per day
(MGD)(8.34)
•300 gpm x 60 min. x 24 hr = 432,000 GPD
•432,000 GPD = .432 MGD
1,000,000 MGD
•12 lbs.per day = 12 lbs.=
(.432)(8.34) 3.6
•3.3 mg/L
300 gpm
Feeding 12 lbs. per day
? MGD
? mg/L